2^2-5=3^2-12x+31

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Solution for 2^2-5=3^2-12x+31 equation: 



2^2-5=3^2-12x+31

We move all terms to the left:

2^2-5-(3^2-12x+31)=0

We add all the numbers together, and all the variables

-(3^2-12x+31)-1=0

We get rid of parentheses

12x-31-1-3^2=0

We add all the numbers together, and all the variables

12x-41=0

We move all terms containing x to the left, all other terms to the right

12x=41

x=41/12

x=3+5/12

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